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Determine the resonant frequency and magnification factor Q of a series RLC circuit in which R= 47Ω, L=12 mH and C= 65pF |
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Answer» t frequency = 180 khz , magnification factor Q = 289Explanation:Resonant frequency = 1/2π√LC( ∵ at Resonant frequency XL = Xc => 2πfL = 1/2πC => F = 1/2π√LC)L = 12 MH = 12 * 10⁻³ LC = 65 pF = 65 * 10⁻¹² Ff = 1/2π√(12 * 10⁻³ * 65 * 10⁻¹²)=> f = 1/2π√(78 *10⁻¹⁴)=> f = 1/2π√(78 *10⁻¹⁴)=> f = 1/2π 78 *10⁻¹⁴)=> f = 1.8 * 10⁵ => f = 180 khz the resonant frequency = 180 khzQ = (Reactive Power/Average Power)Q = XL/R = Xc/R = 2π fr * L/RQ = (1/R) √L/CQ = (1/47) √(12 * 10⁻³ / 65 * 10⁻¹² )=> Q = 289 Learn More:For the series LCR circuit shown in the FIGURE, what is the resonance ...brainly.in/question/12780272 |
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