Determine the no of moles present in 0.55 mg of eletrons

1.	Determine the no of moles present in 0.55 mg of eletrons
Answer» Mass of an electron = 9.1×10^-31 Kg = 9.1×10^-25 mg . Then , number of ELECTRONS (say X) present in 0.55 mg : 0.55/(9.1×10^-25) = 0.604×10^24 Further ; no of moles (say n) = X/N here N is Avogadro's constant . => n= 0.604×10^24/(6.023×10^23) = 1.0034793 . ___________________ HOPE it helps PLEASE mark it as BRAINLIEST

Answer»

Mass of an electron = 9.1×10^-31 Kg

= 9.1×10^-25 mg .

Then , number of ELECTRONS (say X) present in 0.55 mg :

0.55/(9.1×10^-25) = 0.604×10^24

Further ;

no of moles (say n) = X/N

here N is Avogadro's constant .

=> n= 0.604×10^24/(6.023×10^23)

= 1.0034793 .

___________________

HOPE it helps

PLEASE mark it as BRAINLIEST