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Determine the nature of the roots of the quadratic equation 9x2 - 13x + 4 = 0. |
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Answer» 9x2 – 13x + 4 = 0 a = 9, b = −13 and c = 4 ∴ Discriminant = b2 – 4ac = (−13)2 – 4(9)(4) = 169 – 144 = 25 Since 25 is a perfect square. Since D > 0, then equation has two real and unequal roots. |
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