Determine the natural of the root of the quadratic equation 2x²-3x-4=

1.	Determine the natural of the root of the quadratic equation 2x²-3x-4=0
Answer» Step-by-step explanation: The given quadratic equation is ; 2x² + 3x - 4 = 0 . Comparing with the general form of the quadratic equation ax² + bx + c = 0 , we have ; a = 2 , B = 3 , c = -4 Now, The DISCRIMINANT of the given quadratic equation will be given as ; => D = b² - 4AC => D = 3² - 4×2×(-4) => D = 9 + 32 => D = 41 => D > 0 Clearly, The discriminant of the given quadratic equation is greater than zero . Thus, Its roots will be real and distinct .

Determine the natural of the root of the quadratic equation 2x²-3x-4=0

Answer»

Step-by-step explanation:

The given quadratic equation is ;

2x² + 3x - 4 = 0 .

Comparing with the general form of the quadratic equation ax² + bx + c = 0 , we have ;

a = 2 , B = 3 , c = -4

Now,

The DISCRIMINANT of the given quadratic equation will be given as ;

=> D = b² - 4AC

=> D = 3² - 4×2×(-4)

=> D = 9 + 32

=> D = 41

=> D > 0

Clearly,

The discriminant of the given quadratic equation is greater than zero .

Thus,

Its roots will be real and distinct .

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Determine the natural of the root of the quadratic equation 2x²-3x-4=0​

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Determine the natural of the root of the quadratic equation 2x²-3x-4=0