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Determine the moment of inertia of a thin ring about a tangent to the circle in the plane of the ring? |
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Answer» The tangent is parallel to its radius. The distance between two axes is R. Using theorem of parallel axes. Itangent = Idiameter + MR2 = \(\frac{MR^2}{2}+ MR^2 =\frac{3}{2}MR^2\) |
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