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Determine the equation of the line passing through (6,-2),if the sum of its intercepts on the axes is 5 |
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Answer» Answer: let intercepts be (a,0)and (0,B) SLOPE m=-b/a given a+b=5 also m=-(b+2)/6 -(b+2)/6=-b/a 6b=ab+2a put a=b-5 We GET b=-5 or b=2 a=0 a=3 hence eqn is x/3+y/2=1 |
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