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Determine the Ap whise 3rd term is 16 and 7th term exceeds the 5th term by12 |
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Answer» Answer: LET a be the first term of AP. Third term = a + 2d = 16 -----1 seventh term = fifth term + 12 a + 6D = a + 4d + 12 6d - 4d = 12 2d = 12 d = 12/2 d = 6 put value of d in eqn.1 a + 2(6) = 16 a + 12 = 16 a = 16 - 12 a = 4 AP = a, a+d, a+2d,..... = 4, 10, 16,..... Mark me as brainliest!!! |
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