Determine in AP whose third Term is 16 and the 17th term exceeds the 5

1.	Determine in AP whose third Term is 16 and the 17th term exceeds the 5th term by 12
Answer» Answer: First term(a) = 14 and Common DIFFERENCE (d) = 1 Series: 14,15,16,17,18,.......... Step-by-step explanation: THIRD term = a+2d = 16 .......(i) Seventeenth term = FIFTH term +12 a+16d = a+4d + 12 ......(ii) On SOLVING (ii), we get, d = 1 Use this value in (I), we get, a=14 Therefore, series is 14,15,16,17,18.... HOPE it Helped all.... :-)

Determine in AP whose third Term is 16 and the 17th term exceeds the 5th term by 12

Answer»

Answer: First term(a) = 14 and Common DIFFERENCE (d) = 1

Series: 14,15,16,17,18,..........

Step-by-step explanation:

THIRD term = a+2d = 16 .......(i)

Seventeenth term = FIFTH term +12

a+16d = a+4d + 12 ......(ii)

On SOLVING (ii), we get, d = 1

Use this value in (I), we get, a=14

Therefore, series is 14,15,16,17,18....

HOPE it Helped all.... :-)

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Determine in AP whose third Term is 16 and the 17th term exceeds the 5th term by 12

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