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Determine if it is possible to draw ∆PQR with side PQ=11cm,QR=5cm,PR=5cm​

Answer»

ong>Answer:

In a TRIANGLE PQR, PQ =8cm and QR= 7CM. The area of the triangle is 17cm^ 2. Calculate the two possible values of

Area of PQR = (PQ*QR/2)*sin PQR, or

17 = (8*7/2)*sin PQR, or

sin PQR = 17*2/(8*7) = 0.607142857, or

We can find PR^2 = PQ^2+QR^2–2*PQ*QR cos PQR

= 8^2+7^2–2*8*7*cos 37.38319842

= 64+49–112*0.794592695

= 113–88.99438184

= 24.00561816, or

PR = 4.899552853 cm

Area of PQR = 17 = (QR*QR/2)*sin PRQ

=(7*4.899552853/2)*sin PRQ, or

sin PRQ = 17/(7*4.899552853/2) = 0.991344108

Another value of



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