1.

Determine an A.P whose third term is 9 and fifth term is subtracted frm 8th term we get 6

Answer»

Heya !!




3RD term = 9


a + 2d = 9 ---------(1)



And,




8th term - 5th term = 6


A + 7D - ( A + 4D ) = 6



A + 7D - A - 4D = 6




3D = 6


D = 6/3 = 2



Common difference ( D ) = 2




a + 2d = 9



a + 2 × 2 = 9



a = 9-4


a = 5



First term ( A ) = 5





Second term = A + D = 5 + 2 = 7



Third term = A + 2D = 5 + 2 × 2 = 9



Fourth term = A + 3D = 5 + 3 × 2 = 11



Hence,



AP = 5 , 7 , 9 , 11......


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