Determine (5,12,13) is a Pythagorean triplet or not

1.	Determine (5,12,13) is a Pythagorean triplet or not
Answer» QUESTION: Determine (5,12,13) is a Pythagorean triplet or not?? To find: The VERIFICATION of ( 5 , 12 , 13 ) is a Pythagorean triplet. Given: Hypotenuse = 13 cm Height = 12cm Base = 5cm Concept: we know that the Pythagorean triplet can be FOUND by using the formula $h^{2} = p^{2} + b^{2}$ where ; h = hypotenuse p = height b = base Solution: $13^{2} = 12^{2} + 5^{2}$ $13 = \sqrt{12^{2} + 5^{2}}$ $13 = \sqrt{144 + 25}$ $13 = \sqrt{169}$ $13 = 13$ Conclusion: Here the LHS is equal to the RHS , so it is proved that the (5,12,13) is Pythagorean triplet... $h1{text-transform:uppercase;margin-top:90px;text-align:center;font-family:Courier new,monospace;border:3px solid rgb(60,450,500);border-top:none;width:90%;letter-spacing:-6px;box-sizing:border-box;padding-right:5px;border-radius:6px;font-size:35px;font-weight:bold;}h1 span{position:relative;display:inline-block;margin-right:3px;}@keyframes shahir{0%{transform: translateY(0px) rotate(0deg);}40%{transform: translateY(0px) rotate(0deg);}50%{transform: translateY(-50px)rotate(180deg);;}60%{transform: translateY(0px)rotate(360deg);;}100%{transform: translate(0px)rotate(360deg);;}}h1 span{animation: shahir 3s alternate infinite linear;}h1 span:nth-child(1){color:lime;animation-delay: 0s;}h1 span:nth-child(2){color:lightmaroon;animation-delay: 0.2s;}h1 span:nth-child(3){color:red;animation-delay:0s;}h1 span:nth-child(4){color:green;animation-delay: 0.4s;}h1 span:nth-child(5){color:blue;animation-delay: 0.5s;}h1 span:nth-child(6){color:purple;animation-delay: 0.3s;}Aliya♥$

Answer»

QUESTION:

Determine (5,12,13) is a Pythagorean triplet or not??

To find:

The VERIFICATION of ( 5 , 12 , 13 ) is a Pythagorean triplet.

Given:

Hypotenuse = 13 cm

Height = 12cm

Base = 5cm

Concept:

we know that the Pythagorean triplet can be FOUND by using the formula

$h^{2} = p^{2} + b^{2}$

where ;

h = hypotenuse

p = height

b = base

Solution:

$13^{2} = 12^{2} + 5^{2}$

$13 = \sqrt{12^{2} + 5^{2}}$

$13 = \sqrt{144 + 25}$

$13 = \sqrt{169}$

$13 = 13$

Conclusion:

Here the LHS is equal to the RHS , so it is proved that the (5,12,13) is Pythagorean triplet...

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