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n :Find NORMAL reaction and acceleration of block.Diagram : REFER to the attachment.Answer :We know that, Horizontal component of force is responsible for motion of block.Here force acts at angle θ with horizontal directionTherefore horizontal component of force will be Fcosθ and vertical component will be Fsinθ.As per newton's 2nd law of motion,Force = Mass × Acceleration➝ Fcosθ = m × a➝ a = Fcosθ/m ___ (I)Since block moves towards horizontal direction only we can say that,➝ N + Fsinθ = WWhere W DENOTES weight of block➝ N + Fsinθ = MG➝ N = mg - Fsinθ ___ (II)



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