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Derivethe expressionformotionalemfinducedin acondctormovingin auniformmegneticfield . |
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Answer» Solution :Let .PQ. representa conductormovingwithaspeed.V.atrightanglesto themagnetic fluxdensity.B.pointingperpendicularto thesheetof paperandpointingtowardsthepaper.LetRQ= xbethe distancecoveredby theconductor.Magneticflux` phi_(B )= B //x .` Induced emf`=- (d{PHI _(E )))/(dt )=-(d )/(dt )(b//x )` ` i,e.,e=- Bl (dx)/(dt)`  But, ` (-dx )/(dt) = v ` ` thereforee= B/v ` Note : TheLorentzforceactsonachargein aconductorand acts alongPQ. Workdonein movinga charge .Q.fromP TOQ is W= (Lorentzforce)(displacement of thecharge .q. ). i.e.,W= (Bqv )L Bydefinitionelectricp.d `=(W)/(q)=(Bqvl)/(q)=Bvl` Equation(1) and (2)areidentical . |
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