1.

Derive the Meyer’s relationship.

Answer»

We have, q = C × ∆T 

At constant volume, qv = Cv × ∆T = ∆U 

At constant pressure, qp = Cp × ∆T = ∆H 

For 1 mole of an ideal gas, 

∆H = ∆U + ∆(pV) = ∆U + ∆(RT) = ∆U + R∆T 

∴ ∆H = ∆U + R∆T 

On putting the values of ∆H and ∆U, 

Cp ∆T = Cv ∆T + R∆T 

Cp = Cv + R 

Cp – Cv = R, which is the Meyer’s relationship.


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