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Derive the law of reflection of light on the basis of Huygens wave theory. |
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Answer» Solution :Law of REFLECTION : (i) The incident wavefront AB, the reflected wavefront CD and the reflecting surface XY all the in the same plane. (ii) Angle of INCIDENCE `i=/_PAN=90^(@)-/_NAB=/_BAC` Angle of reflection `r=/_NAD=90^(@)-/_DAC=/_DCA` In right angled TRIANGLES ABC and ADC `/_B=/_D=90^(@)`  `BC=AD` and AC is common `:.` The TWO triangles are congruent `:./_BAC=/_DCA` i.e., `i=r` THUS the angle of incidence is equal to angle of reflection. |
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