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Derive the expression for the variation of gravity with respect to the rotation of earth |
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Answer» To calculate the value of g, we should put the values of G, M and R Where G=universal gravitational constant, G=6.7×10 –11 Nm 2 kg −2 mass of the earth, M=6×10 24 kg, and radius of the earth, R=6.4×10 6 m.g= R 2 GM g= (6×10 6 ) 2 6.67×10 −11 ×6×10 24 =9.8m/s 2 Thus, the value of acceleration DUE to gravity of the earth, g=9.8m/s 2 Also we know Weight in nothing but the force EXERTED by the earth with a value of acceleration =9.8m/s 2 Now at the poles the value of acceleration due to gravity is HIGHER as compared to the equator as the constant value of g depends on the radius of the earth which DECREASES when we come down from poles to the equator. |
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