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Derive the equation ignition V=Vo+at from v-tgraph |
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Answer» -v = u + atTO DERIVE :-First equation of motion (v = u + at)DERIVATION :-Let us consider an OBJECT is moving with uniform acceleration along a straight line . Let (u) be the initial velocity at t = 0 . After interval of time (t) , its velocity becomes u.➳ Let OA = u [ t = 0 ]Here in the figure we draw AD ⟂ BC , and BE ⟂ OY.➳ ∠BAD = ϴ. [ say ]Now,➳ Acceleration = SLOPE of Line AB➳ a = TAN ϴ➳ a = BD/AD. [ tan ϴ = P/B ]➳ a = (v - u)/t. [ AD = OC = t ]or, at = v - u.or, v = u + at. [ 1ST Equation of motion ]Hence we proved the required equation of motion (v = u + at) |
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