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Derive the capacitance of parallel plate capacitor with dielectric slab of dielectric constant K |
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Answer» ong>EXPLANATION: Let the TWO plates are KEPT parallel to each other separated be a distance d and cross-sectional area of each plate is A. Electric field by a single thin plate E ′ = 2ϵ oσTotal electric field between the platesE= 2ϵ o
σ + 2ϵ oσ
Or E= ϵσOr E= AeQ
Potential difference between the plates V=Ed⟹ V= AϵoQd
Capacitance C = VQ
Thus we get capacitance of parallel plate CAPACITOR C = dAϵ o
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