1.

Derive PH + POH = 14

Answer»

Kw = [H3O+][OH–] = 10-14

Taking log of minus sign

-log Kw = – log(H3O+) (OH–)

-log Kw = – log[H3O+] – log [OH–]

PKw = PH + POH = 14

pH + pOH = 14



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