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Derive PH + POH = 14 |
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Answer» Kw = [H3O+][OH–] = 10-14 Taking log of minus sign -log Kw = – log(H3O+) (OH–) -log Kw = – log[H3O+] – log [OH–] PKw = PH + POH = 14 pH + pOH = 14 |
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