Saved Bookmarks
| 1. |
Derive magnetic force acts on a charged particle |
|
Answer» For a particle moving in a plane perpendicular to external magnetic field we know that:F = qvBsinθ = mv^2/rorF = mv^2r^-1thus,r^n = r^-1orn = -1-------OR-------When a charge particle is projected with VELOCITY V perpendicular to the magnetic field,B, the force due to field isF = q(vXB), where q is charge of particle. This force is perpendicular to B and v. This fact SHOWS that the particle is moving on circular path in the field. In this situation the magnetic force PROVIDES the centripetal force necessary for circular motion. Therefore ,mv^2/r=qvB.If we stop here, then n=-1. But, if we write mv^2/r=mrw^2, then n =1.Read more on Brainly.in - brainly.in/question/5295433#readmoreExplanation: |
|