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Derive an expressionfor capacitance of a paralle plate capacitor |
Answer» Solution :  Consider two parallel plates P and Qeach of area a and separated by a DISTANCE d in air. Let plate P has surface desity `+sigma` and plate Q has surface CHARGE density`-sigma` and plate Q has surface charge density `-sigma` The electric field between the plates` E = (sigma)/(epsilon_(o)) = (q//A)/(epsilon_(o)` `E= (q)/(Aepsilon_(o)0`, But potentail difference plates , V = ED now capacitanece,`C= (q)/(V)= (q)/(Ed)= (q)/((q)/(Aepsilon_(0))xxd)` `C - (epsilon_(0)A)/(d)` |
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