Derive an expression for super elevation in highways.

1.	Derive an expression for super elevation in highways.
Answer» Answer: v = SPEED in KMPH. R = Radius of the curve in metre. ∴ e = 0.201 – 0.15 = 0.051 per meter of carriage way. ∴ Super ELEVATION = 0.051 * 7 = 0.357 m or 35.7 cm above the inner edge of the road. Hope it helps you.. :) PLS mark me as BRAINLIEST Explanation:

Answer»

Answer:

v = SPEED in KMPH. R = Radius of the curve in metre. ∴ e = 0.201 – 0.15 = 0.051 per meter of carriage way. ∴ Super ELEVATION = 0.051 * 7 = 0.357 m or 35.7 cm above the inner edge of the road.

Hope it helps you.. :)

PLS mark me as BRAINLIEST

Explanation:

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Derive an expression for super elevation in highways.

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