Saved Bookmarks
| 1. |
Derive a Canonical PQR expression for a Boolean function F, represented by the following truth table:PQRF (P, Q, R)00000011010101101000101011011111 |
|
Answer» F (P,Q,R) = (P' + Q' + R) . (P + Q' R) . (P + Q' R).(P' + Q + R') OR F (P,Q,R) = π (0,3,4,5) |
|