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Derivative of tanx |
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Answer» Once all those pieces are in place, the differentiation goes as follows:d(tanx)/dx = d{(sinx)/cosx} /dx = cosx.cosx−sinx.(−sinx)/cos²x(using Quotient Rule) = (cos²x+sin²x)/cos²x = 1/cos²x(using the Pythagorean Identity) =sec²x |
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