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Depression in `f.p.` of an aqueous urea solutio is `1.86^(@) .(K_(f)=1.86^(@) mol^(-1) kg)` Hence, mole`-` fraction of urea in this soluiton is `:A. `0.982`B. `0.567`C. `0.943`D. `0.018` |
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Answer» Correct Answer - 4 As `DeltaT_(f)=` molality `xxK_(f)` `1.86=mxx1.86` molality `=1 mol kg^(-1)` `:. " "` urea `=1 mol` moles of water `=(1000)/(18)=55.55` mole fraction of urea `=(1)/(55.55)=0.018` |
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