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Density of silver metal is 10.8 g c c^(-1), A 20 xx 10 cm thin iron foil is totally immersed in aqueous silver nitrate. Making it as cathode, electrolysis is done using a current strength of 1930 amp for a period of 100 sec. Calculate the thickness of silver metal electroplated on each face of iron foil.

Answer»

Solution :Quantity of ELECTRICITY (Q) = it = `1930 xx 100 = 193000` coul.
Amount of silver depsited using `193000 coul = (193000 xx 108)/(96500) = 216g`
Amount of silvre DEPOSITED on each face of the iron foil = 108 g
Volume of silver electroplated on each face of the iron foil = `w/d = (108)/(10.8) = 10 cc`
The volume is given as, `v = (l + b) xx t, ` if (t) is the thickness and `(l xx b)` is AREA.
thickness of silver electroplated = `("Volume")/("area") = 10/(20 xx 10) = 0.05 cm = 0.5 mm.`


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