1.

Density of a gas is found to be `5.46 g//dm^(3)` at `27^(@)C` and at 2 bar pressure. What will be its density at STP ?

Answer» `d=(MP)/(RT)`. For the same gas at different temperatures and pressure, `(d_(1))/(d_(2))=(P_(1))/(T_(1))xx(T_(2))/(P_(2))`.
Here, `" " d_(1)=5.46 g dm^(-3), T_(1)=27^(@)C=300 K, P_(1)=2" bar"`.
At STP, `" " d_(2)=? " " T_(2)=0^(@)C=273 K, P_(2)=1" bar"`
`:. (5.46 g dm^(-3))/(d_(2))=(2" bar" )/(300 K)xx(273 K)/(1" bar" )`
or `" " d_(2)=3 g dm^(-3)`


Discussion

No Comment Found

Related InterviewSolutions