density of 2.03M acqeous solution of acetic acid is 1.017g mL-1 molecu

1.	density of 2.03M acqeous solution of acetic acid is 1.017g mL-1 molecular mass of acetic acid is 60. calculate the molality of solution
Answer» ONG>Answer: Molecular Mass=60 Molarity=2.03M →Molarity=2.03M means 2.03 moles in 1L of SOLUTION. n=Molar MassGiven Mass 2.03=60Given Mass 2.03×60=121.8g 121.8g of acetic acid in water. →Density=1.017gmL−11mLofsolution⟶1.017ofsolution 1000mLofsolution⟶1017gofsolution Mass of solution = Mass of SOLVENT + Mass of solute 1017g = Mass of solvent + 121.8g 1017−121.8g = Mass of solvent 895.2g = Mass of solvent Molality=Mass of solvent(kg)no. of moles=895.2×10−3kg2.03=2.267m

density of 2.03M acqeous solution of acetic acid is 1.017g mL-1 molecular mass of acetic acid is 60. calculate the molality of solution

Answer» ONG>Answer:

Molecular Mass=60

Molarity=2.03M

→Molarity=2.03M means 2.03 moles in 1L of SOLUTION.

n=Molar MassGiven Mass

2.03=60Given Mass

2.03×60=121.8g

121.8g of acetic acid in water.

→Density=1.017gmL−11mLofsolution⟶1.017ofsolution

1000mLofsolution⟶1017gofsolution

Mass of solution = Mass of SOLVENT + Mass of solute

1017g = Mass of solvent + 121.8g

1017−121.8g = Mass of solvent

895.2g = Mass of solvent

Molality=Mass of solvent(kg)no. of moles=895.2×10−3kg2.03=2.267m