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`DeltaU^(Θ)` of combustion of methane is `-XkJ mol^(-1)`. The value of `DeltaH^(Θ)` isA. `=DeltaU^(Θ)`B. `gt DeltaU^(Θ)`C. `lt DeltaU^(Θ)`D. zero |
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Answer» Correct Answer - c The balance equation for combustion of methane with be `CH_(4)(g)+2O_(2)(g) rarr CO_(2)(g)+2H_(2)O(l)` Thus, `Deltan_(g)=(n_(p)-n_(r))_(g)=1-3=-2` `DeltaH^(Θ)=DeltaU^(Θ)+Deltan_(g)RT=-X-2 RT` Thus, `DeltaH^(Θ) lt DeltaU^(Θ)` |
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