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`DeltaABC` में, `angleABC=5 angleACB` तथा `angleBAC=3 angleACB` हे, तब `angleABC=?`A. `130^(@)`B. `80^(@)`C. `100^(@)`D. `120^(@)` |
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Answer» Correct Answer - C According to question, `(angleABC)/(angleACB) = 5/1` , `(angleBAC)/(angleACB) = 3/1` `therefore angleABC=180^(@)-120^(@)` `angleABC=60^(@)` `angleACB= 180^(@)-105^(@)` `angleACB=180^(@)-105^(@)` `angleACB=75^(@)` `therefore angleABC+angleACB+angleBAC=180^(@)` `angleBAC=180^(@)-75^(@)-60^(@)` `angleBAC=45^(@)` |
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