1.

`DeltaABC` में, `angleABC=5 angleACB` तथा `angleBAC=3 angleACB` हे, तब `angleABC=?`A. `130^(@)`B. `80^(@)`C. `100^(@)`D. `120^(@)`

Answer» Correct Answer - C
According to question,
`(angleABC)/(angleACB) = 5/1` , `(angleBAC)/(angleACB) = 3/1`
`therefore angleABC=180^(@)-120^(@)`
`angleABC=60^(@)`
`angleACB= 180^(@)-105^(@)`
`angleACB=180^(@)-105^(@)`
`angleACB=75^(@)`
`therefore angleABC+angleACB+angleBAC=180^(@)`
`angleBAC=180^(@)-75^(@)-60^(@)`
`angleBAC=45^(@)`


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