1.

Delta_(f) H^(theta) of CO_(2)(g), CO(g), N_(2)O(g) and NO_(2)(g) are respectively -393, -110.81 and 34 ("in "kJ mol^(-1)) at 27^(@)C. Delta H (in kJ) for the reaction : 2NO_(2)(g) + 3CO(g) rarr N_(2)O(g) + 3CO_(3)(g) is

Answer»

836
1460
`-836`
`-1460`

Solution :`DELTA H =Delta H_(F^(@)) (N_(2)O) + 3 Delta H_(f^(@)) (CO_(2)) - (2 Delta H_(f^(@)) (NO_(2)) + 3 Delta H_(f^(@)) (CO_(2))`
`= 81 + 3 (-393) - (2 xx 34 + 3 (-110))`
`= - 836 kJ MOL^(-1)`


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