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`Delta ABC` is right-angled at A and `AD bot BC`. If `BC=13 cm and AC=5 cm`, find the ratio of areas of `Delta ABC and Delta ADC`. |
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Answer» Correct Answer - `169:25` In `Delta BAC and Delta ADC`, we have `angle BAC= angle ADC=90^(@)` `and angle ACB= angle DCA= angle C` `:. Delta BAC~Delta ADC`. [ by AA-similarity] `:. (ar (Delta ABC))/(ar (Delta ADC))=(ar (DeltaBAC))/(ar (Delta ADC))=(BC^(2))/(AC^(2))` |
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