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Deduce an expression for galvanometer to ammeter |
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Answer» If the current IG in the coil produces a full-scale deflection , then the current I in the circuit corresponds to the full-scale deflection . Thus , with a shunt S of the above value , the GALVANOMETER will be an ammeter of range 0 to I ampere (A) . S / G = 1 / 9 EXPLANATION: Hope it'll help you frnds... Mark me as brainliest.... If you can follow me and I'll also follow u |
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