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Decreasing order of stability of `O_(2), O_(2)^(-), O_(2)^(+)` and `O_(2)^(2-)` isA. `O_(2) gt O_(2)^(+) gt O_(2)^(-) gt O_(2)^(-)`B. `O_(2)^(-) gt O_(2)^(2-) gt O_(2)^(+) gt O_(2)`C. `O_(2)^(+) gt O_(2) gt O_(2)^(-) gt O_(2)^(2-)`D. `O_(2)^(2-) gt O_(2)^(-) gt O_(2) gt O_(2)^(+)` |
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Answer» Correct Answer - 3 Stability of `alpha` Bond order i.e, higher to bond order ,greater the stability. According to `MOT` Bond order `=(1)/(2)[N_(b)-N_(a)]` `O_(2)`: Bond order `implies(1)/(2)[10-6]=2` `O_(2)^(-)`: Bond order `implies(1)/(2)[10-7]=1.5` `O_(2)^(+)`: Bond order :` rArr (1)/(2)[10-5]=2.5` `O_(2)^(2-)`: Bond order `implies(1)/(2)[10-8]=1.0` Thus, desreasing order of stability is `O_(2)^(+) gt O_(2) O_(2)^(-) gt O_(2)^(2-)` |
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