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Decreasing order of stability of:1. \( CH _{3}- CH - CH _{3} \)2. \( CH _{3}- CH - OCH _{3} \)\( 3 . CH _{3}- CH - CO - CH _{3} \)a. \( 1>2>3 \)b. \( 2>3>1 \)c. \( 3>1>2 \)d. \( 2>1>3 \) |
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Answer» Considering all given compounds are in cation from - (i) CH3 - \(\overset{+}{CH}\) - CH3 (ii) CH3 - \(\overset{+}{CH}\) - OCH3 (iii) CH3 - \(\overset{+}{CH}\) - \(\overset{O}{\overset{||}{C}}\) - CH3 Compound (1), cation stabilized by hyper conjugation with 6 hydrogen in compound (2), cation stabilized by hyper conjugation as well as by loan pair electron of oxygen. CH3 - \(\overset{+}{CH}\) - O - CH3 ↔ CH3 - CH = \(\overset{+}{O}\) - CH3 it means compound (2) also stablilized by Resonance but in compound (3), the cation stabilized by hyperconjation with 3 hydrogen but destabilized by strong electron with drawing group \(\Big(-\overset{O}{\overset{||}{C}}-CH_3\Big)\) and we also know that Resonance is powerful Than Hyper conjugation because of that compound (2) is more stabilized than compound (1) Hence order of stability 2 > 1 > 3 |
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