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Decomposition of phosphine on tungsten at low pressure is a first order reaction. This is because the |
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Answer» Since the options are not given, I am giving the answer BASED on the options from another website. Rate = k[PH₃] The rate is dependent on the surface coverage as under conditions of low pressure, the surface area covered will be proportional to the partial pressure of PHOSPHINE (PH₃). So, it will be a FIRST order reaction with respect to Phosphine (PH₃). The EQUATIONS are here - θ = 1+kP1+kP θ = fraction of surface area covered at low pressure θ = k P |
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