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De broglie wavelength of an electron travelling one percent speed of light |
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Answer» DE broglie wavelength is GIVEN by the ratio of the planks constant and the momentum of the particle wavelength = h/p = h/mv, where m is mass of particle and p is it's momentum and v is it's velocity v= SPEED of LIGHT(c) /100 = 6.626*10^-34 JS / 9.1*10^-31 Kg* 3*10^6m/s = 0.243* 10^-9 m = 2.43* 10^ -10 m or 2.43 A° (Because 1A°= 10^-10m) The debroglie wavelength of the electron is 2.43A° |
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