Saved Bookmarks
| 1. |
De broglie wavelength of an electron moving with one tenth of the speed of light is |
|
Answer» e here is your answer...Mass of an electron =9.1×10−31kg9.1×10−31kgSpeed of the electron = 10% of C = 29979245.829979245.8 (or 30,000,00030,000,000, depends on what c value you TAKE)Therefore: de BROGLIE’s wavelength’s FORMULA is λ=hmvλ=hmv.And so, here the wavelength would be λ=6.62×10−349.1×10−31×29979245.8λ=6.62×10−349.1×10−31×29979245.8Which would give us 6.62×0.0019.1×29979245.8=2.42×10−11m=0.0242 |
|