1.

ddx[(x+1)(x2+1)(x4+1)(x8+1)]=(15xp−16xq+1)(x−1)−2⇒(p,q)=

Answer»

ddx[(x+1)(x2+1)(x4+1)(x8+1)]=(15xp16xq+1)(x1)2

(p,q)=





Discussion

No Comment Found