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DAVINDRA THREE-IN-ONESolve the following pair of lincar equation by using crossmultiplication method:2x + y = 5 and 3x + 2y = 8oto |
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Answer» x=3 and y=-1 equally X=2 and y=1 right answere it is the xbarabr 2 and y barar 1 x= -3 y=1 is correct solution. x=3 and y= -1 equally right answers Please like X=2,y=1 by cross multiplication x=2 y=1 is the correct answer x=2,y=1 this is a right answer 2x + y =5,then, y = 5 - 2x ......- 3 and eq. 2 3x + 2y = 8then, put eq.3 in eq.23x + 5 - 2x = 8x + 5 = 8x = 3 put in eq. 3then y = -1 Y=1 is the right answer. x=2 y=1this is right answer 2x+y=5-3x+2y=8x=2y=1-. - 2x+y=5 (1)×3 3x+2y=8 (2)×2 6x+3y=15 6x+4y=16- - - 3y-4y=15-16 -y =-1 y =1 from equation (1)2x+y =52x+1=5 2x=5-1 x =4/2 x= 2. answer3x+2y=8 (2) the correct answer is x=2 y=1 x=2, y=1 is the correct answer 2x+y=5y=5-2xnow put y value in second iquation3x+2y=83x+2(5-2x)3x+10-4x=8-x+10=8-x=8-10-x=-2x=2now put x value in first equation2x+y=52(2)+y=54+y=5y=5-4y=1so x=2 and y= 1 x=18/7,y=-1/7 х=2 αnd ч=1 αftєr ѕσlvíng hσw tσ ѕσlvє fírѕt єquαl єq1 αnd αq2 let,2x+y=5___(1)3x+2y=8___(2)Multiplying equation (1) by 2,4x+2y=10___(3)Subtracting equation (2) from equation (3), 4x+2y=10- 3x+2y=8_____________ X. =2X=2put X=2 in equation (1),2×2+y=5 4+y=5 y=5-4 y=1 X=2 and y=1 is solution x = 2 and y = 1 this right answer x = 3 and y = -1 equally x=-3,y=1 is your correct answer x=2 y=1 is the write answer 2x+y=5___________(1)×23x+2y=8_____________(2)तब,4x+2y=10_________(3)3x+2y=8___________(2)_____________________घटाने परx+0=2X=2,समीकरण (1)मे X=2 रखने पर 2x+y=5___(1)2×2+y=54+y=5y=5-4y=1 |
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