Darpogo. If HCF Ca, b = 12 Es axb=1800,- I and Its 2 cm.2. The LCM & H

1.	Darpogo. If HCF Ca, b = 12 Es axb=1800,- I and Its 2 cm.2. The LCM & HCP of two Numbersis 180 and 6 Respectively . IfOne of the number is 30.- find the other number.
Answer» Step-by-step explanation: 2 SOL: Given that, LCM of two numbers = 180 HCF of two numbers = 6 One of the NUMBER = 30 Let the other number be X Now, Product of two numbers = LCM x HCF 30 × X = 180 × 6 X = 1080 / 30 X = 36

Darpogo. If HCF Ca, b = 12 Es axb=1800,- I and Its 2 cm.2. The LCM & HCP of two Numbersis 180 and 6 Respectively . IfOne of the number is 30.- find the other number.

Answer»

Step-by-step explanation:

2 SOL:

Given that,

LCM of two numbers = 180

HCF of two numbers = 6

One of the NUMBER = 30

Let the other number be X

Now,

Product of two numbers = LCM x HCF

30 × X = 180 × 6

X = 1080 / 30

X = 36

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Darpogo. If HCF Ca, b = 12 Es axb=1800,- I and Its 2 cm.2. The LCM & HCP of two Numbersis 180 and 6 Respectively . IfOne of the number is 30.- find the other number.​

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Darpogo. If HCF Ca, b = 12 Es axb=1800,- I and Its 2 cm.2. The LCM & HCP of two Numbersis 180 and 6 Respectively . IfOne of the number is 30.- find the other number.