Daniel is painting the wall and ceiling of a cuboidal hall with Length

1.	Daniel is painting the wall and ceiling of a cuboidal hall with Length breadth and height of 15 metre 10 metre and 7 respectively from each can of paint hundred square of area is painted how many cans of paint will she need to paint the room
Answer» Answer: 5 cans Step-by-step explanation: Given :- lenght of room = 15 mtr breath of room = 10mtr HEIGHT of room = 7 mtr find *out* *the* *requirement* of *paint* *cans* if *100m² can* be *painted* by a *can* *Solution*:- as we know that a room has 4 walls and a roof also so no. of surfaces is 5 as room is cuboid shape that's why alternate walls of the room have the same area so => 2(15×7+10×7) 7 is height of the room it means sides have same height => 2(105+70) => 2(175) => 350 m² also room has a roof so area of ceil is = 15×10 = 150 now total area is= 350+150 = 500m² can required is = 500/100 = 5 cans**

Daniel is painting the wall and ceiling of a cuboidal hall with Length breadth and height of 15 metre 10 metre and 7 respectively from each can of paint hundred square of area is painted how many cans of paint will she need to paint the room

Answer»

Answer:

5 cans

Step-by-step explanation:

Given :-

lenght of room = 15 mtr

breath of room = 10mtr

HEIGHT of room = 7 mtr

find out the requirement of paint cans if 100m² can be painted by a can

Solution:-

as we know that a room has 4 walls and a roof also so no. of surfaces is 5

as room is cuboid shape that's why alternate walls of the room have the same area so

=> 2(15×7+10×7) 7 is height of the room it means sides have same height

=> 2(105+70)

=> 2(175)

=> 350 m²

also room has a roof

area of ceil is = 15×10 = 150

now total area is= 350+150 = 500m²

can required is = 500/100 = 5 cans