ΔABC is right triangle in which ∠ABC=90∘. A circle is drawn on side AB as diameter intersecting AC in P. PQ is the tangent to the circle when intersects BC in Q. Prove that tangent at P bisects the side BC.

ΔABC is right triangle in which ∠ABC=90∘. A circle is drawn on si

1.	ΔABC is right triangle in which ∠ABC=90∘. A circle is drawn on side AB as diameter intersecting AC in P. PQ is the tangent to the circle when intersects BC in Q. Prove that tangent at P bisects the side BC.
Answer» $Δ A B C$ is right triangle in which $∠ A B C = 90^{\circ}$ . A circle is drawn on side AB as diameter intersecting AC in P. PQ is the tangent to the circle when intersects BC in Q. Prove that tangent at P bisects the side BC.

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ΔABC is right triangle in which ∠ABC=90∘. A circle is drawn on side AB as diameter intersecting AC in P. PQ is the tangent to the circle when intersects BC in Q. Prove that tangent at P bisects the side BC.

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