ΔABC is right-angled at A. AD is perpendicular to BC, AB = 5 cm, BC =

1.	ΔABC is right-angled at A. AD is perpendicular to BC, AB = 5 cm, BC = 13 cm and AC = 12 cm. Find the area of ΔABC. Also, find the length of AD.
Answer» Given. In ΔABC, ∠A = 90° AB = 5cm; AC = 12cm; AD ⊥ BC; BC = 13cm. Now area of ΔABC = 12 × base × height = 12 x AB x AC = 12 × 5 × 12 = 30cm² Also area of MBC = 12 × BC × AD 30 = 12 × 13 × AD ∴ \(\frac {30\times2}{13} = \frac {60}{13} = 4\frac {8}{13}\) cm

ΔABC is right-angled at A. AD is perpendicular to BC, AB = 5 cm, BC = 13 cm and AC = 12 cm. Find the area of ΔABC. Also, find the length of AD.

Answer»

Given.

In ΔABC, ∠A = 90°

AB = 5cm; AC = 12cm; AD ⊥ BC; BC = 13cm.

Now area of ΔABC = 12 × base × height

= 12 x AB x AC = 12 × 5 × 12 = 30cm²

Also area of MBC = 12 × BC × AD

30 = 12 × 13 × AD

∴ \(\frac {30\times2}{13} = \frac {60}{13} = 4\frac {8}{13}\) cm