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ΔABC is an isosceles triangle in which AB=AC. Show that ∠B=∠C. (Hint : Draw AP⊥ BC) (Using RHS congruence rule) |
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Answer» Answer: ∠B = ∠C Step-by-step explanation: ΔABC is an isosceles triangle in which AB=AC Let draw AP ⊥ BC in Δ ABP AB² = AP² + BP² in Δ ACP AC² = AP² + CP² AB = AC Squaring both sides => AB² = AC² so equating both EQUATION AP² + BP² = AP² + CP² => BP² = CP² => BP = CP in Δ ABP & Δ ACP AB = AC AP is commom BP = CP all sides are equal => Δ ABP ≅ Δ ACP => ∠B = ∠C |
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