ΔABC ≈ΔDEF, AB = 5 cm , DF = 15 cm, and DE = 12 cm is given find A

1.	ΔABC ≈ΔDEF, AB = 5 cm , DF = 15 cm, and DE = 12 cm is given find AC.
Answer» ong>ANSWER: As per the dimensions GIVE in the QUESTIONS, From the question it is GIVEN that, △DEF∼△LMN So, AB/ED=AC/EF=BC/DF Consider AB/ED=AC/EF 5/12=7/EF By cross multiplication, EF=(7×12)/5 EF=16.8cm Now, consider AB/ED=BC/DF 5/12=BC/15 BC=(5×15)/12 BC=75/12 BC=6.25. solution

ΔABC ≈ΔDEF, AB = 5 cm , DF = 15 cm, and DE = 12 cm is given find AC.

Answer»

As per the dimensions GIVE in the QUESTIONS,

From the question it is GIVEN that,

△DEF∼△LMN

So, AB/ED=AC/EF=BC/DF

Consider AB/ED=AC/EF

5/12=7/EF

By cross multiplication,

EF=(7×12)/5

EF=16.8cm

Now, consider AB/ED=BC/DF

5/12=BC/15

BC=(5×15)/12

BC=75/12

BC=6.25.

solution