D- glucose, on treating with methanol in the presence of dry HCl gives methyl glucoside according to the following reaction: Mention true (T) and False (F) from the following statements: S1: The glucosides do not reduce fehling's solution. S2: The glucosides do not react with hydrogen cyanide or hydroxylamine. S3: Behaviour of glucosides as stated in S1 and S2 indicates the absence of free −CHO group. S4: The two forms of glucosides are enantiomers.

D- glucose, on treating with methanol in the presence of dry HCl gives

1.	D- glucose, on treating with methanol in the presence of dry HCl gives methyl glucoside according to the following reaction: Mention true (T) and False (F) from the following statements: S1: The glucosides do not reduce fehling's solution. S2: The glucosides do not react with hydrogen cyanide or hydroxylamine. S3: Behaviour of glucosides as stated in S1 and S2 indicates the absence of free −CHO group. S4: The two forms of glucosides are enantiomers.
Answer» D- glucose, on treating with methanol in the presence of dry $H C l$ gives methyl glucoside according to the following reaction: Mention true (T) and False (F) from the following statements: $S_{1} :$ The glucosides do not reduce fehling's solution. $S_{2} :$ The glucosides do not react with hydrogen cyanide or hydroxylamine. $S_{3} :$ Behaviour of glucosides as stated in $S_{1}$ and $S_{2}$ indicates the absence of free $- C H O$ group. $S_{4} :$ The two forms of glucosides are enantiomers.