D and E are points on the base BC of ΔABC such that AD=AE and ∠BAD=

1.	D and E are points on the base BC of ΔABC such that AD=AE and ∠BAD=∠CAE. Prove that ΔABC is an isosceles triangle.
Answer» Answer: first of all you have to SEE given Given that: AD=AE,BD=EC To prove: AB=AC Since, AD=AE △ADE is an isosceles triangle. AF⊥DE,DF=FE (Properties of isosceles triangle) Now, BD+DF=FE+EC⇒BF=FC In △AFB and △AFC, ⇒BF=FC ∠AFB=∠AFC ⇒AF is COMMON side Thus △AFB≅AFC Therefore, AB=AC .....(By CPCT) Step-by-step EXPLANATION: thats yours answer

D and E are points on the base BC of ΔABC such that AD=AE and ∠BAD=∠CAE. Prove that ΔABC is an isosceles triangle.

Answer»

Answer:

first of all you have to SEE given

Given that: AD=AE,BD=EC

To prove: AB=AC

Since, AD=AE △ADE is an isosceles triangle.

AF⊥DE,DF=FE (Properties of isosceles triangle)

Now, BD+DF=FE+EC⇒BF=FC

In △AFB and △AFC,

⇒BF=FC

∠AFB=∠AFC

⇒AF is COMMON side

Thus △AFB≅AFC

Therefore, AB=AC .....(By CPCT)

Step-by-step EXPLANATION:

thats yours answer

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D and E are points on the base BC of ΔABC such that AD=AE and ∠BAD=∠CAE. Prove that ΔABC is an isosceles triangle.

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