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•d. A stone thrown vertically upwards withinitial velocity u reaches a height 'h'before coming down. Show that thetime taken to go up is same as the timetaken to come down.If the value of a suddenly becomes twice |
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Answer» When stone throw upward with initial VELOCITY, uFinal velocity at maximum height, v=0Apply kinematic EQUATION of motion.v=u+att= av−u = −g0−u Apply kinematic equation of motion.s=ut+ 21 at 2 h=u( gu )− 21 g( gu ) 2 u= 2gh TIME,t= gu = g2gh t= g2h ........(1)(ii) When stone drop from height hApply kinematic equation of motion.v 2 −u 2 =2ghv= 2gh Apply kinematic equation of motion.v=u+att= av−u = g2gh −0 = g2h .......(2)From (1 ) and (2) it is PROVED that the time taken to go up is same as the time taken to come down. Explanation:hope its helps |
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