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(D) 1664. From a solid cylinder of height 10 cm andradius of the base 6 cm, a cone of sameheight and same base is removed. Thevolume of the solid cone is:(A) 240 T cm3(C) 120m cm3(B) 360 t cm3(D) 120 cm3 |
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Answer» TSA of remaining solid = TSA of cylinder - TSA of cone= 2πr(r+h) - πr(r+l) = πr(2r + 2h - r + l) =22 / 7 × 6 ( 20+6+11.66)=22 / 7 × 6 × 37.66=710.16cm^2volume of remaining solid = Volume of Cylinder - volume of cone =πr^2h - 1/3πr^2h =2 /3πr^2h=2 /3×22 /7×6×6×10=753.6cm^3 |
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